Hi,
In one application group by files are loaded on June 5th 2014 but they have loaded in 4 duplicate copies when i try to delete i am little bit confused because first 2 files having same Partial load id and Second 2 have same partial id.
In 4 files i want to keep one file and remove rest of them.
kIndly help me
thanks in advance and appricate the prior response.
Hi Rajesh
You can use arsadmin command. You have to pass load id here. So you can give three load ids one by one which you want to delete.
arsadmin unload -u <user> -p <pass> -h <host> -g <app_group> -L <load_id>
OR you can use System Load application . Search your application group there and find the load id you want to delete and Right click- Unload.
Thank you for your reply kasim,
Problem is here for two files having load id as 17780-1-0-372785FAA and rest of two having load id as 17780-1-0-372784FAA,
If i use arsadmin unload command then it will remove all the files related to 17780-1-0-372784FAA and 17780-1-0-372785FAA then all files will be out.
kindly suggest
Check out arsdoc delete.
-JD.
Hi JD,
As per your suggestion i have gone through the command but when i try to delete command with Load id it will delete the total files rather than keeping 1 file below is the sample command.
arsdoc delete -h servername -f DS2CAS -v -i "where company = '6246' and LoadId='17780-1-0-372785FAA'" -S 5/1/14,5/31/14 -v
If i use this command then it will delete the all files with load id given but i want to keep one file from 4 files rest of 3 need to be deleted
Suggest me in the command is there any chance to mention the count of files need to be deleted in duplicates if so.
Kindly confirm and provide me the command.
Attached the image For Information.
Could you check if you have 87 messages 2 times or 4 times in system log?
If it is 2 times, then the problem could be with the index parameters you have provided. In this case you will not be able to retain a unique entry. You need to remove the 2 loads and correct the indexing parameters and re-index/load the file.
Hi,
In system 87 messages Out of 4 Files Two files having same load and rest of two files having same load id as stated in the above conversation.
But as per your comments only one day it worked like that rest of day i am able to see only single entry of files.
Kindly suggest
Sounds like you had duplicate data in the two loads or the indexing created two copies, is that correct? If that is the case you aren't going to be able to get to only one copy. You'll have to do a delete and reload of the data as Frederick suggested.
Compare the file and layout that comes regularly and that came on the day of exception, there could be some thing wired which would have caused the problem
Ive seen that happen before. A file comes from whatever system, mainframe, documaker, exstream, and one day person xyz runs an invalid job and it causes all kinds of headaches.
I have asked the user to generate a new copy of file with no dups and i have unloaded all the dups and reload the new batch file.
Is the solution i have tired.
Thanks a lot for every one who helped me in this issue
Theres only so much cmod can do
I think a lot of the lines of business that use it think it is used to fix their junk data, ignore their invalid data, etc.
Sometimes it just takes pushing back to get good data. Currently dealing with that now.